Answer


(1)
y'
= {x2(3x+1)}'
= (x2)'(3x+1) + x2(3x+1)'
= 2x(3x+1) + x2¥3
=9x2 + 2x

(2)
y'
= {excos x}'
= (ex)'cos x + ex(cos x)'
= excos x - exsin x

(3)
y'
= (sin x cos x)'
=(sin x)'cos x + sin x(cos x)'
=cos2x - sin2x
=cos 2x